Aptitude Ratio And ProportionPage 3
17. | | If X/Y = 3/4, Find 4X + 5Y/5X - 2Y = ? | | (a)31:4 | | (b)33:4 | | (c)32:5 | | (d)32:7 |
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Answer is: DGiven, X/Y = 3/4
= 4X + 5Y/5X - 2Y
= Y[4(X/Y) + 5]/Y[5(X/Y) - 2]
= [4(3/4) + 5]/[5(3/4) - 2]
= 8/(15/4) - 2
= 8/(7/4)
= 32/7
18. | | Divide Rs 828 in the 9 : 3 ? | | (a)601:227 | | (b)603:225 | | (c)605:223 | | (d)621:207 |
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Answer is: DSum of ratio terms (9+3) = 12
First part is = Rs (828 x 9/12) =Rs 621
Second part is = Rs (828 x 3/12) = Rs 207
19. | | A bag contains 50 p, 25 p and 10 p coins in the ratio 5 : 9 : 4, amounting to ₹206. Find the number of coins of 50 p. | | (a)50 | | (b)100 | | (c)200 | | (d)300 |
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Answer is: CLet the number of 50 p, 25 p and 10 p coins be 5x, 9x and 4x respectively.
Then, 5x/2 + 9x/4 +4x/10 = 206
50x + 45x + 8x = 4120
103x = 4120
X = 40
∴ Number of 50 p coins = (5x40) = 200
20. | | A mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the RATIO BECOMES 4 : 5. Find the quantity of alcohol in the given mixture. | | (a)5 | | (b)10 | | (c)15 | | (d)20 |
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Answer is: BLet the quantity of alcohol and water be 4x litres and 3x litres respectively.
Then, 4x/((3x+5) )= 4/5
20 x = 4 (3x +5)
8x = 20 =
X = 2.5
∴ Quantity of alcohol = (4 x 2.5) litres = 10 litres
21. | | The salaries of A, B and C are in ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be the new ratio of their salaries ? | | (a)23:33:60 | | (b)23:25:60 | | (c)23:33:55 | | (d)24:33:60 |
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Answer is: ALet A = 2k, B = 3k and c = 5k
A’s new salary = 115/100 of 2k = (115/100x2k ) = 23/10 k
B’s new salary = 110/100 of 3k = (110/100x3k) = 33/10k
C’s new salary = 120/100 of 5k = (120/100x5k) = 6k
∴ New ratio = 23/10k : 33/10k : 6k
A:B:C = 23:33:60
22. | | In a mixture of 60 litres, The ratio of milk and water is 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is ? | | (a)40 | | (b)50 | | (c)60 | | (d)70 |
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Answer is: CQuantity of milk = (60 x 2/3) litres = 40 litres
Quantity of water in it = (60-40) litres = 20 litres
New ratio required = 1:2
Let quantity of water to be added further be x litres.
Then, milk : water = 40 : (20 + x)
Now, 40/((20+x) ) = 1/2
20 + x = 80
X = 60
∴ Quantity of water to be further added = 60 litres
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