Reasoning Clock And CalenderPage 1
1. | | At what angle the hands of a clock are inclined at 15 minutes past 5? | | (a)72(1/2)° | | (b)67(1/2)o | | (c)58(1/2)o | | (d)64o |
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Answer is: BAt 15 min. past 5, the minute hand is at 3 and hour and slightly ahead of 5.
Now, angle through which hour hand shifts in 15 min. = 15(1/2)o = 7(1/2)o
So, Angle at 15 min. past 5 = 60 + 7(1/2)o = 67(1/2)o.
2. | | A clock is set right at 8 am. The clock gains 10 minutes in 24 hours. What will be the right time when the clock indicates 1 pm on the following day? | | (a)11:40 pm | | (b)12:48 pm | | (c)12 pm | | (d)10 pm |
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Answer is: BFrom 8 am of a particular day to 1 pm of the following day = 29 h.
Now, the clock gains 10 min in 24 h, it means that 24 h 10 min of this clock is equal to 24 h of the correct clock.
145/6 hour of this clock = 24 h of the correct clock.
29 h of this clock = (24/145) x 6 x 29 = 28 h. 48 min. of correct clock.
29 h of this clock = 28 h. 48 min. of the correct clock.
It means that the clock in question is 12 min. faster than the correct clock. Therefore, when clock indicates 1pm the correct time will be 48 min. past 12.
3. | | What was the day on 26th January. 1950, when 1st Republic day of India was celebrated? | | (a)Monday | | (b)Tuesday | | (c)Thursday | | (d)Friday |
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Answer is: C26 January 1950 means 1949 year and 26 days.
1600 year have 0 odd day,
300 year have 1 odd day,
49 year have (12 leap year and 37 ordinary years)
So, [(12 x 366) + (37 x 365)] days
[4392 + 13505] days = 17897 day
17897 days = 2556 weeks + 5 days
So, 49 years have 5 odd days.
Total number of odd days = 0 + 1 + 5 + 5 = 11 days.
Hence, the days on 26th Jan, 1950 was Thursday.
4. | | If the day after tomorrow is a Sunday, what was it day before yesterday? | | (a)Wednesday | | (b)Thursday | | (c)Friday | | (d)Saturday |
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Answer is: AToday – Friday. So, the yesterday day before – Wednesday.
5. | | What will be the angle between hour hand and minute hand, if clock shows 8:30 pm? | | (a)90o | | (b)75o | | (c)60o | | (d)85o |
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Answer is: BAngle = (360 x 2.5)/12 = 75o
6. | | Reaching the place of meeting on Tuesday 15 min. before 8:30 h, Anuj found himself half an hour earlier than the man who was 40 min late. What was the scheduled time of the meeting? | | (a)8:00 h | | (b)8:05 h | | (c)8:15 h | | (d)8:45 h |
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Answer is: BAnuj reached the place of meeting at 8:15 h, he reached 30 min earlier than the man who was 40 min late. He reached 10 min. Hence, the scheduled time of the meeting was 8:05 h.
7. | | A clock buzzes 1 time at 1 O’clock, 2 times at 2 O’clock, 3 times at 3 O’clock and so on. What will be the total number of buzzes in a day? | | (a)150 | | (b)156 | | (c)160 | | (d)166 |
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Answer is: BNumber of buzzes in a day = [12(12+1)/2]x2 = 156
8. | | How many times the hands of a clock are is at right angle in a day? | | (a)22 | | (b)24 | | (c)44 | | (d)48 |
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Answer is: CIn, 12 h, they are at right angles, 22 times.
So, in 24 h, they are at right angles, 44 times.
9. | | How many times do the hands of a clock coincide in a day? | | (a)24 | | (b)22 | | (c)21 | | (d)20 |
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Answer is: BForm the properties of the clock, we know that hands of a clock coincide once in every hour but between 11 o’clock and 1 o’clock. They coincide only once. Therefore, the hands of a clock coincide 11 times in every 12 h.
Hence, they will coincide (11 x 2) = 22 times in 24 h
10. | | How many times do the hands of a clock points towards each other in day? | | (a)22 | | (b)24 | | (c)21 | | (d)20 |
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Answer is: AThe hands of a clock point each other 11 times in every 12 h (Because between 5 and 7, they point towards each other only once at 6 o’clock).
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