Aptitude Simple And Compound InterestPage 1
1. | Find the interest under simple interest for a principal of ₹1200 at an interest rate of 5% per annum for a period of 4 years. | (a)240 | (b)260 | (c)320 | (d)450 |
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Answer is: AI = PNR/100
Here, P = 1200
N = 4
 R = 5%
I = (1200 x 4 x 5)/100 = ₹240.
I = ₹240.
2. | What is the interest earned on ₹10,000 for 2 years at 10% per annum simple interest?(in ₹) | (a)2000 | (b)1500 | (c)2500 | (d)3000 |
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Answer is: AI = PNR/100
I = (10000 x 2 x 10)/100
I = 2000.
3. | What is the interest earned on ₹10000 for 2 years at 10% per annum compound interest, compounded annually? | (a)210 | (b)420 | (c)315 | (d)630 |
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Answer is: AInterest for the first year
= (1000 x 1 x 10)/100 = 100
Principal for second year
= 1000 + 100 = 1100
Interest for the second year = (1100 x 1 x 10)/100 = 110
Hence, Total interest for the two years = 100 + 110 = ₹210.
4. | If ₹2000 amount to ₹2200 in 2 years under simple interest, what is the rate of interest per annum? | (a)15% | (b)10% | (c)5% | (d)20% |
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Answer is: CI = Amount - Principal = 2200 - 2000 = ₹200.
I = PNR/100
200 = (2000 x 2 x R)/100 = 5%
5. | If ₹20000 amount to ₹24200 in 2 years under compound interest, what is the rate of interest per annum? | (a)10% | (b)20% | (c)15% | (d)Cannot be determined |
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Answer is: AA = P(1 + R/100)^N
24200 = 20000(1 + R/100)^2
1.21 = (1 + R/100)^2
R = 10%
6. | What is the interest earned in the first year on ₹200 at 10% per annum compound interest, interest compounded every 6 months? | (a)₹20 | (b)₹20.50 | (c)₹25 | (d)₹23.20 |
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Answer is: BInterest for first six months = (200 x 1/2 x 10)/100 = ₹10
Principal for next six months = 200 + 10 = ₹210
Interest for next six months = (210 x 1/2 x 10)/100 = ₹10.5
Total interest = 10 + 10.5 = ₹20.5
7. | At what rate percent per annum will a sum of money double in 16 years? | (a)6 | (b)13/2 | (c)25/4 | (d)31/5 |
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Answer is: CLet principal = P.
Then, S.I. = P
And T = 16 years.
R = (100 x P)/(P x 16)% = 25/4% p.a.
8. | A sum of ₹1550 is lent out into two parts, one at 8% and another one at 6%. If the total annual income is ₹106, find the money lent at each rate. | (a)800 | (b)900 | (c)1000 | (d)700 |
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Answer is: BLet the sum lent at 8% be ₹ X and that at 6% be ₹ (1550 - X).
[8 x 1 x X]/100 + [(1550 - X) x 6 x 1]/100 = 106
8X + 9300 - 6X = 10600
2X = 1300
X = 650
Money lent at 8% = ₹650.
Money lent at 6% = ₹(1550 - 650) = ₹900.
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