Reasoning Equality And InequalityPage 2
Section2
Direction:In these questions relationship between different elements is shown in statements. The statements are followed by conclusions. Study the conclusions based on the given statement and select the appropriate answer.
1.  Statements:
M > U > L â‰¤ N
L â‰¥ Y > A
Conclusions:
Y < N
M > N
N = Y
M > A  (a)Only 1 , 2 and 3 are true  (b)Only 1 and 2 are true  (c)All 1, 2 3 and 4 are true  (d)Only 4 and Either 1 or 3 are true 

Answer is: DM > U > L â‰¤ N â€¦â€¦..(1)
L â‰¥ Y > A â€¦â€¦â€¦..(2)
Combining 1 and 2, we get
M > U > L â‰¥ Y > A and A < Y â‰¤ L â‰¤ N
Thus, Y â‰¤ N is true.
Hence, Y < N may be true.
And Y = N may be true.
So, conclusion 1 and 3 make a complementary pair.
Thus, either 1 or 3 is true.
Again, we can't compare M and N. Hence 2 is not true.
But M > A is true. Hence, 4 is true.
Hence only 4 and either 1 or 3 are true.
2.  Statements:
M > U > L â‰¤ N
L â‰¥ Y > A
Conclusions:
Y < N
M > N
N = Y
M > A  (a)Only 1 , 2 and 3 are true  (b)Only 2 is true  (c)Only 4 and Either 1 or 3 are true  (d)All 1, 2 3 and 4 are true 

Answer is: CM > U > L â‰¤ N â€¦â€¦..(1)
L â‰¥ Y > A â€¦â€¦â€¦..(2)
Combining 1 and 2, we get
M > U > L â‰¥ Y > A and A < Y â‰¤ L â‰¤ N
Thus, Y â‰¤ N is true.
Hence, Y < N may be true.
And Y = N may be true.
So, conclusion 1 and 3 make a complementary pair.
Thus, either 1 or 3 is true.
Again, we can't compare M and N. Hence 2 is not true.
But M > A is true. Hence, 4 is true.
Hence only 4 and either 1 or 3 are true.
3.  Statements:
J â‰¥ A > D = E
L < A < M
Conclusions:
M < J
J > L
D > L
E < M  (a)Only 1 , 2 and 3 are true  (b)Only 2 and 4 are true  (c)Only 1 and Either 2 or 4 are true  (d)All 1, 2 3 and 4 are true 

Answer is: BJ â‰¥ A > D = E â€¦â€¦.(1)
L < A < M â€¦â€¦â€¦.(2)
Combining equation (1) and (2), we get
M > A > D = E â€¦â€¦.(3)
J â‰¥ A < M â€¦â€¦â€¦.(4)
J â‰¥ A > L â€¦â€¦â€¦.(5)
L < A > D â€¦â€¦.(6)
Thus, from equation 4, we can't compare J and M. Hence, 1 is not true.
From 5, J > L is true. Hence 2 is true.
Again, from 6, we can't compare D and L. Hence 3 is not true.
Now, from (3), M > E or E < M is true. Hence (4) is true.
Thus, only 2 and 4 are true.
4.  Statements:
Y > F â‰¤ O â‰¤ P
F â‰¥ U < T
Conclusions:
Y > P
T < F
O > T
P < U  (a)Only 1 , 2 and 3 are true  (b)Only 1 and 2 are true  (c)All 1, 2 3 and 4 are true  (d)none is true 

Answer is: DY > F â‰¤ O â‰¤ P â€¦â€¦â€¦â€¦(1)
F â‰¥ U < T â€¦â€¦â€¦â€¦.(2)
Thus, from (1) we can't compare Y and P. Hence 1 is not true. Again, from (2) we can't compare F and T. So, 2 is not true.
T > U â‰¤ F â‰¤ O â‰¤ P
Thus, we can't compare O and T. Hence (3) is not true.
Again, U â‰¤ P is true. So, (4) (P < U) is not true. Hence none is true.
5.  Statements:
M > H â‰¤ Y â‰¤ R < U = Z â‰¥ E
Conclusions:
M > R
Z â‰¤ R
R > E
Z > H  (a)Only 1 , 2 and 3 are true  (b)Only 4 is true  (c)Only 2 is true  (d)All 1, 2 3 and 4 are true 

Answer is: BM > H â‰¤ Y â‰¤ R < U = Z â‰¥ E
Thus, we can't compare M and R. Hence (1) is not true.
Again, H < Z or Z > H is true. Hence 4 is true.
And R < Z or Z > R is true. Hence 2 (Z â‰¤ R) is not true. We can't compare R and E. Hence 3 is not true.
6.  Statements:
P > Q â‰¤ C â‰¤ B = M > D
Conclusions:
M > Q
D â‰¤ Q
M = Q
C > D  (a)Only 1 or 3 are true  (b)Only 1 , 2 and 3 are true  (c)Only 1 and Either 2 or 4 are true  (d)All 1, 2 3 and 4 are true 

Answer is: AP > Q â‰¤ C â‰¤ B = M > D
Thus, Q â‰¤ M is true. So, M > Q may be true.
And M = Q may be true. So, conclusion 1 and 3 make a complimentary pair.
Again, we can't compare D and Q, or C and D. So, 2 and 4 are not true.
7.  Statements:
A â‰¥ B = C, B < D â‰¤ E
Conclusions:
D > A
E > C  (a)If only conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either conclusion 1 or 2 follows  (d)If neither conclusion 1 nor 2 follows 

Answer is: BA â‰¥ B = C < D â‰¤ E
D > A is not true.
E > C is true.
8.  Statements:
L > U â‰¥ K, Z < U < R
Conclusions:
L > Z
K < R  (a)If only Conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either Conclusion 1 or 2 follow  (d)If both conclusions 1 and 2 follow 

Answer is: DGiven that
L > U â€¦â€¦..(1)
U â‰¥ K . â€¦..(2)
Z < U â€¦â€¦.(3) and
U < R â€¦â€¦.(4).
Combining 1 and 3, we get
L > U > Z or L > Z. hence 1 follows.
Combining 2 and 4, we get
K â‰¤ U < R or K < R. Hence 2 is follows.
9.  Statements:
L > U â‰¥ K, Z < U < R
Conclusions:
L > Z
K < R  (a)If only Conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either Conclusion 1 or 2 follow  (d)If both conclusions 1 and 2 follow 

Answer is: DGiven that
L > U â€¦â€¦..(1)
U â‰¥ K . â€¦..(2)
Z < U â€¦â€¦.(3) and
U < R â€¦â€¦.(4).
Combining 1 and 3, we get
L > U > Z or L > Z. hence 1 follows.
Combining 2 and 4, we get
K â‰¤ U < R or K < R. Hence 2 is follows.
10.  Statements:
Y < J = P â‰¥ R > I
Conclusions:
J > I
Y < R  (a)If only Conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either Conclusion 1 or 2 follow  (d)If neither Conclusion 1 nor 2 follow 

Answer is: AY < J = P â‰¥ R > I
J > I is true.
Y < R is not true
11.  Statements:
V â‰¥ K > M = N, M > S, T < K
Conclusions:
T < N
V = S  (a)If only Conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either Conclusion 1 or 2 follow  (d)If neither conclusion 1 nor 2 follows 

Answer is: CV â‰¥ K > M = N > S
K > T
T < N is not true.
V = S is not true.
12.  Statements:
F â‰¤ X < A, R < X â‰¤ E
Conclusions:
F â‰¤ E
R < F  (a)If only Conclusion 1 follows  (b)If only Conclusion 2 follows  (c)If either Conclusion 1 or 2 follow  (d)If neither conclusion 1 nor 2 follows 

Answer is: AGiven that â€“
F â‰¤ X â€¦â€¦..(1)
X < A â€¦â€¦..(2)
R < X â€¦â€¦â€¦(3) and
X â‰¤ E â€¦â€¦.(4)
Combining 1 and 4, we get
F â‰¤ X â‰¤ E or F â‰¤ E.
Hence 1 follows
From 1 and 3, R and F can't compared. Hence 2 does not follow.
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