## Reasoning Equality And InequalityPage 2

###### Section-2
Direction:In these questions relationship between different elements is shown in statements. The statements are followed by conclusions. Study the conclusions based on the given statement and select the appropriate answer.

1.

 Statements: M > U > L â‰¤ N L â‰¥ Y > A Conclusions: Y < N M > N N = Y M > A (a)Only 1 , 2 and 3 are true (b)Only 1 and 2 are true (c)All 1, 2 3 and 4 are true (d)Only 4 and Either 1 or 3 are true
Answer is: DM > U > L â‰¤ N â€¦â€¦..(1)
L â‰¥ Y > A â€¦â€¦â€¦..(2)
Combining 1 and 2, we get
M > U > L â‰¥ Y > A and A < Y â‰¤ L â‰¤ N
Thus, Y â‰¤ N is true.
Hence, Y < N may be true.
And Y = N may be true.
So, conclusion 1 and 3 make a complementary pair.
Thus, either 1 or 3 is true.
Again, we can't compare M and N. Hence 2 is not true.
But M > A is true. Hence, 4 is true.
Hence only 4 and either 1 or 3 are true.

2.

 Statements: M > U > L â‰¤ N L â‰¥ Y > A Conclusions: Y < N M > N N = Y M > A (a)Only 1 , 2 and 3 are true (b)Only 2 is true (c)Only 4 and Either 1 or 3 are true (d)All 1, 2 3 and 4 are true
Answer is: CM > U > L â‰¤ N â€¦â€¦..(1)
L â‰¥ Y > A â€¦â€¦â€¦..(2)
Combining 1 and 2, we get
M > U > L â‰¥ Y > A and A < Y â‰¤ L â‰¤ N
Thus, Y â‰¤ N is true.
Hence, Y < N may be true.
And Y = N may be true.
So, conclusion 1 and 3 make a complementary pair.
Thus, either 1 or 3 is true.
Again, we can't compare M and N. Hence 2 is not true.
But M > A is true. Hence, 4 is true.
Hence only 4 and either 1 or 3 are true.

3.

 Statements: J â‰¥ A > D = E L < A < M Conclusions: M < J J > L D > L E < M (a)Only 1 , 2 and 3 are true (b)Only 2 and 4 are true (c)Only 1 and Either 2 or 4 are true (d)All 1, 2 3 and 4 are true
Answer is: BJ â‰¥ A > D = E â€¦â€¦.(1)
L < A < M â€¦â€¦â€¦.(2)
Combining equation (1) and (2), we get
M > A > D = E â€¦â€¦.(3)
J â‰¥ A < M â€¦â€¦â€¦.(4)
J â‰¥ A > L â€¦â€¦â€¦.(5)
L < A > D â€¦â€¦.(6)
Thus, from equation 4, we can't compare J and M. Hence, 1 is not true.
From 5, J > L is true. Hence 2 is true.
Again, from 6, we can't compare D and L. Hence 3 is not true.
Now, from (3), M > E or E < M is true. Hence (4) is true.
Thus, only 2 and 4 are true.

4.

 Statements: Y > F â‰¤ O â‰¤ P F â‰¥ U < T Conclusions: Y > P T < F O > T P < U (a)Only 1 , 2 and 3 are true (b)Only 1 and 2 are true (c)All 1, 2 3 and 4 are true (d)none is true
Answer is: DY > F â‰¤ O â‰¤ P â€¦â€¦â€¦â€¦(1)
F â‰¥ U < T â€¦â€¦â€¦â€¦.(2)
Thus, from (1) we can't compare Y and P. Hence 1 is not true. Again, from (2) we can't compare F and T. So, 2 is not true.
T > U â‰¤ F â‰¤ O â‰¤ P
Thus, we can't compare O and T. Hence (3) is not true.
Again, U â‰¤ P is true. So, (4) (P < U) is not true. Hence none is true.

5.

 Statements: M > H â‰¤ Y â‰¤ R < U = Z â‰¥ E Conclusions: M > R Z â‰¤ R R > E Z > H (a)Only 1 , 2 and 3 are true (b)Only 4 is true (c)Only 2 is true (d)All 1, 2 3 and 4 are true
Answer is: BM > H â‰¤ Y â‰¤ R < U = Z â‰¥ E
Thus, we can't compare M and R. Hence (1) is not true.
Again, H < Z or Z > H is true. Hence 4 is true.
And R < Z or Z > R is true. Hence 2 (Z â‰¤ R) is not true. We can't compare R and E. Hence 3 is not true.

6.

 Statements: P > Q â‰¤ C â‰¤ B = M > D Conclusions: M > Q D â‰¤ Q M = Q C > D (a)Only 1 or 3 are true (b)Only 1 , 2 and 3 are true (c)Only 1 and Either 2 or 4 are true (d)All 1, 2 3 and 4 are true
Answer is: AP > Q â‰¤ C â‰¤ B = M > D
Thus, Q â‰¤ M is true. So, M > Q may be true.
And M = Q may be true. So, conclusion 1 and 3 make a complimentary pair.
Again, we can't compare D and Q, or C and D. So, 2 and 4 are not true.

7.

 Statements: A â‰¥ B = C, B < D â‰¤ E Conclusions: D > A E > C (a)If only conclusion 1 follows (b)If only Conclusion 2 follows (c)If either conclusion 1 or 2 follows (d)If neither conclusion 1 nor 2 follows
Answer is: BA â‰¥ B = C < D â‰¤ E
D > A is not true.
E > C is true.

8.

 Statements: L > U â‰¥ K, Z < U < R Conclusions: L > Z K < R (a)If only Conclusion 1 follows (b)If only Conclusion 2 follows (c)If either Conclusion 1 or 2 follow (d)If both conclusions 1 and 2 follow
L > U â€¦â€¦..(1)
U â‰¥ K . â€¦..(2)
Z < U â€¦â€¦.(3) and
U < R â€¦â€¦.(4).
Combining 1 and 3, we get
L > U > Z or L > Z. hence 1 follows.
Combining 2 and 4, we get
K â‰¤ U < R or K < R. Hence 2 is follows.

9.

 Statements: L > U â‰¥ K, Z < U < R Conclusions: L > Z K < R (a)If only Conclusion 1 follows (b)If only Conclusion 2 follows (c)If either Conclusion 1 or 2 follow (d)If both conclusions 1 and 2 follow
L > U â€¦â€¦..(1)
U â‰¥ K . â€¦..(2)
Z < U â€¦â€¦.(3) and
U < R â€¦â€¦.(4).
Combining 1 and 3, we get
L > U > Z or L > Z. hence 1 follows.
Combining 2 and 4, we get
K â‰¤ U < R or K < R. Hence 2 is follows.

10.

 Statements: Y < J = P â‰¥ R > I Conclusions: J > I Y < R (a)If only Conclusion 1 follows (b)If only Conclusion 2 follows (c)If either Conclusion 1 or 2 follow (d)If neither Conclusion 1 nor 2 follow
Answer is: AY < J = P â‰¥ R > I
J > I is true.
Y < R is not true

11.

 Statements: V â‰¥ K > M = N, M > S, T < K Conclusions: T < N V = S (a)If only Conclusion 1 follows (b)If only Conclusion 2 follows (c)If either Conclusion 1 or 2 follow (d)If neither conclusion 1 nor 2 follows
Answer is: CV â‰¥ K > M = N > S
K > T
T < N is not true.
V = S is not true.

12.

 Statements: F â‰¤ X < A, R < X â‰¤ E Conclusions: F â‰¤ E R < F (a)If only Conclusion 1 follows (b)If only Conclusion 2 follows (c)If either Conclusion 1 or 2 follow (d)If neither conclusion 1 nor 2 follows
F â‰¤ X â€¦â€¦..(1)
X < A â€¦â€¦..(2)
R < X â€¦â€¦â€¦(3) and
X â‰¤ E â€¦â€¦.(4)
Combining 1 and 4, we get
F â‰¤ X â‰¤ E or F â‰¤ E.
Hence 1 follows
From 1 and 3, R and F can't compared. Hence 2 does not follow.